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6q^2-8q-14=0
a = 6; b = -8; c = -14;
Δ = b2-4ac
Δ = -82-4·6·(-14)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-20}{2*6}=\frac{-12}{12} =-1 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+20}{2*6}=\frac{28}{12} =2+1/3 $
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